Consider the line -x+3y=1Find the equation of the line that is perpendicular to this line and passes through the point (7,-5). Find the equation of the line that is parallel to this line and passes through (7,-5). Equation of perpendicular line: Equation of parallel line:
Accepted Solution
A:
the line -x+3y=1 can be moved into slope intercept form to get slope. slope is what matters for questions that asks about perpendicular/parallel...
isolate y to get slope intercept form
-x+3y=1 add x to both sides 3y = x + 1 divide both sides by 3 y = (x+1)/3 y = x/3 + 1/3
the slope is 1/3 because x/3 is the same as 1/3 * x.
the line that is perpendicular to this line has a slope that is the negative recirpocal of the original slope like.
perpendicular line slope: -3. (reciprocal of 1/3 is 3; then make that negative).
Told that this perp line passes through (7,-5), using slope intercept form y = mx + b with unknown y-intercept b value:
y = -3x + b
since (7,-5) means at x = 7, y = -5, plug those numbers in to solve for b
-5 = -3(7) + b -5 = -21 + b b = -5 + 21 b = 16
perpendicular line: y = -3x + 16
for the parallel line has the same slope as the original slope of parallel line: 1/3
we are told that parpall line goes through (7,-5) so using the unfinished slope-intercept form y = mx + b with unfinishe dinfo: we have
y = 1/3 x + b
since at x = 7 we have y = -5, plug it in
-5 = (1/3)(7) + b -5 = 7/3 + b b = -5 - 7/3 b = -15/3 - 7/3 .... same denominator for fraction add/subtract b = -22/3